2(b^2+8b+32)=32

Solution for 2(b^2+8b+32)=32 equation:

Simplifying
2(b2 + 8b + 32) = 32

Reorder the terms:
2(32 + 8b + b2) = 32
(32 * 2 + 8b * 2 + b2 * 2) = 32
(64 + 16b + 2b2) = 32

Solving
64 + 16b + 2b2 = 32

Solving for variable 'b'.

Reorder the terms:
64 + -32 + 16b + 2b2 = 32 + -32

Combine like terms: 64 + -32 = 32
32 + 16b + 2b2 = 32 + -32

Combine like terms: 32 + -32 = 0
32 + 16b + 2b2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(16 + 8b + b2) = 0

Factor a trinomial.
2((4 + b)(4 + b)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Solution
b = {-4, -4}